
You may recall that an array arr is a mountain array if and only if:
arr.length >= 3
There exists some index i ( 0-indexed ) with 0 < i < arr.length - 1 such that:
arr[0] < arr[1] < ... < arr[i - 1] < arr[i]
arr[i] > arr[i + 1] > ... > arr[arr.length - 1]
Given an integer array arr , return the length of the longest subarray, which is a mountain . Return 0 if there is no mountain subarray.
1 <= arr.length <= 10 ^40 <= arr[i] <= 10 ^4Follow up:Can you solve it using only one pass?Can you solve it in O(1) space?