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Flip Columns For Maximum Number of Equal Rows

arrayhash tablematrix

Problem Statement

You are given an m x n binary matrix matrix .

You can choose any number of columns in the matrix and flip every cell in that column (i.e., Change the value of the cell from 0 to 1 or vice versa).

Return the maximum number of rows that have all values equal after some number of flips .

Examples

Example 1
Input: matrix = [[0,1],[1,1]]
Output: 1
After flipping no values, 1 row has all values equal.
Example 2
Input: matrix = [[0,1],[1,0]]
Output: 2
After flipping values in the first column, both rows have equal values.
Example 3
Input: matrix = [[0,0,0],[0,0,1],[1,1,0]]
Output: 2
After flipping values in the first two columns, the last two rows have equal values.

Constraints

m == matrix.length
n == matrix[i].length
1 <= m, n <= 300
matrix[i][j] is either 0 or 1 .
🤔
Medium
Difficulty
Topic Info
ModuleDSA
CategoryArray
Sub-topicHash Table
Tags
arrayhash tablematrix
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