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DSA
HardArray

Count of Smaller Numbers After Self

arraybinary searchdivide and conquer

Problem Statement

Given an integer array nums , return an integer array counts where counts[i] is the number of smaller elements to the right of nums[i] .

Examples

Example 1
Input: nums = [5,2,6,1]
Output: [2,1,1,0]
To the right of 5 there are 2 smaller elements (2 and 1). To the right of 2 there is only 1 smaller element (1). To the right of 6 there is 1 smaller element (1). To the right of 1 there is 0 smaller element.
Example 2
Input: nums = [-1]
Output: [0]
Example 3
Input: nums = [-1,-1]
Output: [0,0]

Constraints

1 <= nums.length <= 10 ^5
-10 ^4 <= nums[i] <= 10 ^4
😤
Hard
Difficulty
Topic Info
ModuleDSA
CategoryArray
Sub-topicBinary Search
Tags
arraybinary searchdivide and conquerbinary indexed treesegment treemerge sortordered set
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