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3Sum

arraytwo pointerssorting

Problem Statement

Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j , i != k , and j != k , and nums[i] + nums[j] + nums[k] == 0 .

Notice that the solution set must not contain duplicate triplets.

Examples

Example 1
Input: nums = [-1,0,1,2,-1,-4]
Output: [[-1,-1,2],[-1,0,1]]
nums[0] + nums[1] + nums[2] = (-1) + 0 + 1 = 0. nums[1] + nums[2] + nums[4] = 0 + 1 + (-1) = 0. nums[0] + nums[3] + nums[4] = (-1) + 2 + (-1) = 0. The distinct triplets are [-1,0,1] and [-1,-1,2]. Notice that the order of the output and the order of the triplets does not matter.
Example 2
Input: nums = [0,1,1]
Output: []
The only possible triplet does not sum up to 0.
Example 3
Input: nums = [0,0,0]
Output: [[0,0,0]]
The only possible triplet sums up to 0.

Constraints

3 <= nums.length <= 3000
-10 ^5 <= nums[i] <= 10 ^5
🤔
Medium
Difficulty
Topic Info
ModuleDSA
CategoryArray
Sub-topicTwo Pointers
Tags
arraytwo pointerssorting
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