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Odd Even Jump

arraydynamic programmingstack

Problem Statement

You are given an integer array arr . From some starting index, you can make a series of jumps. The (1 ^st , 3 ^rd , 5 ^th , ...) jumps in the series are called odd-numbered jumps , and the (2 ^nd , 4 ^th , 6 ^th , ...) jumps in the series are called even-numbered jumps . Note that the jumps are numbered, not the indices.

You may jump forward from index i to index j (with i < j ) in the following way:

During odd-numbered jumps (i.e., jumps 1, 3, 5, ...), you jump to the index j such that arr[i] <= arr[j] and arr[j] is the smallest possible value. If there are multiple such indices j , you can only jump to the smallest such index j .

During even-numbered jumps (i.e., jumps 2, 4, 6, ...), you jump to the index j such that arr[i] >= arr[j] and arr[j] is the largest possible value. If there are multiple such indices j , you can only jump to the smallest such index j .

It may be the case that for some index i , there are no legal jumps.

A starting index is good if, starting from that index, you can reach the end of the array (index arr.length - 1 ) by jumping some number of times (possibly 0 or more than once).

Return the number of good starting indices .

Examples

Example 1
Input: arr = [10,13,12,14,15]
Output: 2
From starting index i = 0, we can make our 1st jump to i = 2 (since arr[2] is the smallest among arr[1], arr[2], arr[3], arr[4] that is greater or equal to arr[0]), then we cannot jump any more. From starting index i = 1 and i = 2, we can make our 1st jump to i = 3, then we cannot jump any more. From starting index i = 3, we can make our 1st jump to i = 4, so we have reached the end. From starting index i = 4, we have reached the end already. In total, there are 2 different starting indices i = 3 and i = 4, where we can reach the end with some number of jumps.
Example 2
Input: arr = [2,3,1,1,4]
Output: 3
From starting index i = 0, we make jumps to i = 1, i = 2, i = 3: During our 1st jump (odd-numbered), we first jump to i = 1 because arr[1] is the smallest value in [arr[1], arr[2], arr[3], arr[4]] that is greater than or equal to arr[0]. During our 2nd jump (even-numbered), we jump from i = 1 to i = 2 because arr[2] is the largest value in [arr[2], arr[3], arr[4]] that is less than or equal to arr[1]. arr[3] is also the largest value, but 2 is a smaller index, so we can only jump to i = 2 and not i = 3 During our 3rd jump (odd-numbered), we jump from i = 2 to i = 3 because arr[3] is the smallest value in [arr[3], arr[4]] that is greater than or equal to arr[2]. We can't jump from i = 3 to i = 4, so the starting index i = 0 is not good. In a similar manner, we can deduce that: From starting index i = 1, we jump to i = 4, so we reach the end. From starting index i = 2, we jump to i = 3, and then we can't jump anymore. From starting index i = 3, we jump to i = 4, so we reach the end. From starting index i = 4, we are already at the end. In total, there are 3 different starting indices i = 1, i = 3, and i = 4, where we can reach the end with some number of jumps.
Example 3
Input: arr = [5,1,3,4,2]
Output: 3
We can reach the end from starting indices 1, 2, and 4.

Constraints

1 <= arr.length <= 2 * 10 ^4
0 <= arr[i] < 10 ^5
😤
Hard
Difficulty
Topic Info
ModuleDSA
CategoryArray
Sub-topicDynamic Programming
Tags
arraydynamic programmingstacksortingmonotonic stackordered set
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